BTU/Pound-°F to Joule/Kilogram-Kelvin Converter

Specific Heat Capacity Converter

6 units available

Decimals:

From

To

4,186.8

1 BTU/(lb·°F) = 4,186.8 J/(kg·K)

Formula:

J/(kg·K) = BTU/(lb·°F) × 4,186.8

With your value: 1 BTU/(lb·°F) = 4,186.8 J/(kg·K)

Other BTU/Pound-°F to Joule/Kilogram-Kelvin conversions

2 BTU/(lb·°F) to J/(kg·K)3 BTU/(lb·°F) to J/(kg·K)4 BTU/(lb·°F) to J/(kg·K)5 BTU/(lb·°F) to J/(kg·K)6 BTU/(lb·°F) to J/(kg·K)7 BTU/(lb·°F) to J/(kg·K)8 BTU/(lb·°F) to J/(kg·K)

BTU/Pound-°F to Joule/Kilogram-Kelvin Conversion Table

BTU/Pound-°F (BTU/(lb·°F))	Joule/Kilogram-Kelvin (J/(kg·K))
0.5	2,093.4
1	4,186.8
2	8,373.6
5	20,934
10	41,868
15	62,802
20	83,736
25	104,670
50	209,340
100	418,680
250	1,046,700
500	2,093,400
1000	4,186,800

Joule/Kilogram-Kelvin to BTU/Pound-°F Conversion Table

Joule/Kilogram-Kelvin (J/(kg·K))	BTU/Pound-°F (BTU/(lb·°F))
0.5	0.000119
1	0.000239
2	0.000478
5	0.001194
10	0.002388
15	0.003583
20	0.004777
25	0.005971
50	0.011942
100	0.023885
250	0.059711
500	0.119423
1000	0.238846

Where these values come from

Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.

BTU/Pound-°F (BTU/(lb·°F))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

Joule/Kilogram-Kelvin (J/(kg·K))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

How to Convert BTU/Pound-°F to Joule/Kilogram-Kelvin

To convert from BTU/Pound-°F (BTU/(lb·°F)) to Joule/Kilogram-Kelvin (J/(kg·K)), multiply the value by 4,186.8.

Formula: J/(kg·K) = BTU/(lb·°F) × 4,186.8

Reverse: BTU/(lb·°F) = J/(kg·K) × 0.0002388459

Step-by-Step Example

Start with your value in BTU/Pound-°F. For example: 5 BTU/(lb·°F)
Multiply by the conversion factor: 5 x 4,186.8
The result is: 20,934 J/(kg·K)

About BTU/Pound-°F

The btu/pound-°f (BTU/(lb·°F)) is a unit of specific heat capacity. One btu/pound-°f equals 4186.8 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

About Joule/Kilogram-Kelvin

The joule/kilogram-kelvin (J/(kg·K)) is a unit of specific heat capacity. One joule/kilogram-kelvin equals 1 base unit. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

Frequently Asked Questions

How many Joule/Kilogram-Kelvin are in 1 BTU/Pound-°F?

There are exactly 4,186.8 Joule/Kilogram-Kelvin in 1 BTU/Pound-°F. This means the conversion factor from BTU/Pound-°F to Joule/Kilogram-Kelvin is 4,186.8.

What is the formula to convert BTU/Pound-°F to Joule/Kilogram-Kelvin?

The formula to convert BTU/Pound-°F to Joule/Kilogram-Kelvin is: J/(kg·K) = BTU/(lb·°F) × 4,186.8. For example, to convert 10 BTU/Pound-°F to Joule/Kilogram-Kelvin, you would multiply 10 by 4,186.8.

What is a BTU/Pound-°F?