Foot-Pound to Newton-Centimeter Converter
Convert Foot-Pound (ft·lbf) to Newton-Centimeter (N·cm) instantly. 1 ft·lbf = 135.581795 N·cm.
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11 units available
1 ft·lbf = 135.581795 N·cm
Formula:
N·cm = ft·lbf × 135.58179483With your value: 1 ft·lbf = 135.58179483 N·cm
Other Foot-Pound to Newton-Centimeter conversions
Foot-Pound to Newton-Centimeter Conversion Table
| Foot-Pound (ft·lbf) | Newton-Centimeter (N·cm) |
|---|---|
| 0.5 | 67.790897 |
| 1 | 135.581795 |
| 2 | 271.16359 |
| 5 | 677.908974 |
| 10 | 1,355.817948 |
| 15 | 2,033.726922 |
| 20 | 2,711.635897 |
| 25 | 3,389.544871 |
| 50 | 6,779.089741 |
| 100 | 13,558.179483 |
| 250 | 33,895.448708 |
| 500 | 67,790.897415 |
| 1000 | 135,581.79483 |
Newton-Centimeter to Foot-Pound Conversion Table
| Newton-Centimeter (N·cm) | Foot-Pound (ft·lbf) |
|---|---|
| 0.5 | 0.003688 |
| 1 | 0.007376 |
| 2 | 0.014751 |
| 5 | 0.036878 |
| 10 | 0.073756 |
| 15 | 0.110634 |
| 20 | 0.147512 |
| 25 | 0.184391 |
| 50 | 0.368781 |
| 100 | 0.737562 |
| 250 | 1.843905 |
| 500 | 3.687811 |
| 1000 | 7.375621 |
Where these values come from
Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.
Foot-Pound (ft·lbf)
Torque
Derived from the newton metre; imperial torque uses the exact pound-force and foot.
Source: NIST Special Publication 811, Guide for the Use of the International System of Units
National Institute of Standards and Technology (US) · Reviewed 2026-07-01
Newton-Centimeter (N·cm)
Torque
Derived from the newton metre; imperial torque uses the exact pound-force and foot.
Source: NIST Special Publication 811, Guide for the Use of the International System of Units
National Institute of Standards and Technology (US) · Reviewed 2026-07-01
How to Convert Foot-Pound to Newton-Centimeter
To convert from Foot-Pound (ft·lbf) to Newton-Centimeter (N·cm), multiply the value by 135.58179483.
Formula: N·cm = ft·lbf × 135.58179483
Reverse: ft·lbf = N·cm × 0.0073756215
Step-by-Step Example
- Start with your value in Foot-Pound. For example: 5 ft·lbf
- Multiply by the conversion factor: 5 x 135.58179483
- The result is: 677.908974 N·cm
About Foot-Pound
Foot-pound force (ft·lbf) is a unit of torque in the imperial system. It represents one pound of force acting at a distance of one foot from a pivot point.
Common uses: automotive specs, US engineering, tooling.
About Newton-Centimeter
The newton-centimeter (N·cm) is a unit of torque. One newton-centimeter equals 0.01 newton metres. UnitConvertLab converts it against every other torque unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.
Common uses: torque calculations, engineering and science, education.
Frequently Asked Questions
How many Newton-Centimeter are in 1 Foot-Pound?
There are exactly 135.58179483 Newton-Centimeter in 1 Foot-Pound. This means the conversion factor from Foot-Pound to Newton-Centimeter is 135.58179483.
What is the formula to convert Foot-Pound to Newton-Centimeter?
The formula to convert Foot-Pound to Newton-Centimeter is: N·cm = ft·lbf × 135.58179483. For example, to convert 10 Foot-Pound to Newton-Centimeter, you would multiply 10 by 135.58179483.
What is a Foot-Pound?
Foot-pound force (ft·lbf) is a unit of torque in the imperial system. It represents one pound of force acting at a distance of one foot from a pivot point.
What is a Newton-Centimeter?
The newton-centimeter (N·cm) is a unit of torque. One newton-centimeter equals 0.01 newton metres. UnitConvertLab converts it against every other torque unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.
What are the common uses of Foot-Pound?
The Foot-Pound is commonly used in automotive specs, US engineering, tooling.
Related Torque Conversions
Cite this page
UnitConvertLab. (2026). Foot-Pound to Newton-Centimeter converter. UnitConvertLab. Retrieved from https://unitconvertlab.com/convert/foot_pound_torque-to-newton_centimeter