Megaelectron Volt to Foot-Pound Converter

Energy Converter

27 units available

Decimals:

From

To

1.181705e-13

1 MeV = 1.181705e-13 ft·lbf

Formula:

ft·lbf = MeV × 1.181705e-13

With your value: 1 MeV = 1.181705e-13 ft·lbf

How big is that?

Everyday references on a logarithmic scale, all expressed in megaelectron volt so you can sanity-check the result.

Your value1.00 MeV

Heartbeat (6.2e+12× your value)6.24e+12 MeV

AA battery charge (6.2e+16× your value)6.24e+16 MeV

Slice of bread (1.7e+18× your value)1.75e+18 MeV

Daily food intake (5.2e+19× your value)5.24e+19 MeV

Litre of petrol (2.1e+20× your value)2.13e+20 MeV

Other Megaelectron Volt to Foot-Pound conversions

2 MeV to ft·lbf 3 MeV to ft·lbf 4 MeV to ft·lbf 5 MeV to ft·lbf 6 MeV to ft·lbf 7 MeV to ft·lbf 8 MeV to ft·lbf

Megaelectron Volt to Foot-Pound Conversion Table

Megaelectron Volt (MeV)	Foot-Pound (ft·lbf)
0.5	5.908524e-14
1	1.181705e-13
2	2.363410e-13
5	5.908524e-13
10	1.181705e-12
15	1.772557e-12
20	2.363410e-12
25	2.954262e-12
50	5.908524e-12
100	1.181705e-11
250	2.954262e-11
500	5.908524e-11
1000	1.181705e-10

Foot-Pound to Megaelectron Volt Conversion Table

Foot-Pound (ft·lbf)	Megaelectron Volt (MeV)
0.5	4.231175e+12
1	8.462350e+12
2	1.692470e+13
5	4.231175e+13
10	8.462350e+13
15	1.269353e+14
20	1.692470e+14
25	2.115588e+14
50	4.231175e+14
100	8.462350e+14
250	2.115588e+15
500	4.231175e+15
1000	8.462350e+15

Where these values come from

Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.

Megaelectron Volt (MeV)

Energy

Exact conversion

Derived from the joule (1 J = 1 kg·m²/s²). Thermochemical and IT calories, BTU and kWh are exact defined multiples.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

Foot-Pound (ft·lbf)

Energy

Exact conversion

Derived from the joule (1 J = 1 kg·m²/s²). Thermochemical and IT calories, BTU and kWh are exact defined multiples.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

How to Convert Megaelectron Volt to Foot-Pound

To convert from Megaelectron Volt (MeV) to Foot-Pound (ft·lbf), multiply the value by 1.181705e-13.

Formula: ft·lbf = MeV × 1.181705e-13

Reverse: MeV = ft·lbf × 8.462350e+12

Step-by-Step Example

Start with your value in Megaelectron Volt. For example: 5 MeV
Multiply by the conversion factor: 5 x 1.181705e-13
The result is: 5.908524e-13 ft·lbf

About Megaelectron Volt

The megaelectron volt (MeV) is a unit of energy and work. One megaelectron volt equals 1.602177 × 10^-13 joules. UnitConvertLab converts it against every other energy unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: energy calculations, engineering and science, education.

About Foot-Pound

The foot-pound (ft·lbf) is a unit of energy and work. One foot-pound equals 1.355817948 joules. UnitConvertLab converts it against every other energy unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: energy calculations, engineering and science, education.

Frequently Asked Questions

How many Foot-Pound are in 1 Megaelectron Volt?

There are exactly 1.181705e-13 Foot-Pound in 1 Megaelectron Volt. This means the conversion factor from Megaelectron Volt to Foot-Pound is 1.181705e-13.

What is the formula to convert Megaelectron Volt to Foot-Pound?

The formula to convert Megaelectron Volt to Foot-Pound is: ft·lbf = MeV × 1.181705e-13. For example, to convert 10 Megaelectron Volt to Foot-Pound, you would multiply 10 by 1.181705e-13.

What is a Megaelectron Volt?