Newton-Centimeter to Foot-Pound Converter

Torque Converter

11 units available

Decimals:

From

To

0.007376

1 N·cm = 0.007376 ft·lbf

Formula:

ft·lbf = N·cm × 0.0073756215

With your value: 1 N·cm = 0.00737562 ft·lbf

Other Newton-Centimeter to Foot-Pound conversions

2 N·cm to ft·lbf 3 N·cm to ft·lbf 4 N·cm to ft·lbf 5 N·cm to ft·lbf 6 N·cm to ft·lbf 7 N·cm to ft·lbf 8 N·cm to ft·lbf

Newton-Centimeter to Foot-Pound Conversion Table

Newton-Centimeter (N·cm)	Foot-Pound (ft·lbf)
0.5	0.003688
1	0.007376
2	0.014751
5	0.036878
10	0.073756
15	0.110634
20	0.147512
25	0.184391
50	0.368781
100	0.737562
250	1.843905
500	3.687811
1000	7.375621

Foot-Pound to Newton-Centimeter Conversion Table

Foot-Pound (ft·lbf)	Newton-Centimeter (N·cm)
0.5	67.790897
1	135.581795
2	271.16359
5	677.908974
10	1,355.817948
15	2,033.726922
20	2,711.635897
25	3,389.544871
50	6,779.089741
100	13,558.179483
250	33,895.448708
500	67,790.897415
1000	135,581.79483

Where these values come from

Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.

Newton-Centimeter (N·cm)

Torque

Exact conversion

Derived from the newton metre; imperial torque uses the exact pound-force and foot.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

Foot-Pound (ft·lbf)

Torque

Exact conversion

Derived from the newton metre; imperial torque uses the exact pound-force and foot.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

How to Convert Newton-Centimeter to Foot-Pound

To convert from Newton-Centimeter (N·cm) to Foot-Pound (ft·lbf), multiply the value by 0.0073756215.

Formula: ft·lbf = N·cm × 0.0073756215

Reverse: N·cm = ft·lbf × 135.58179483

Step-by-Step Example

Start with your value in Newton-Centimeter. For example: 5 N·cm
Multiply by the conversion factor: 5 x 0.0073756215
The result is: 0.036878 ft·lbf

About Newton-Centimeter

The newton-centimeter (N·cm) is a unit of torque. One newton-centimeter equals 0.01 newton metres. UnitConvertLab converts it against every other torque unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: torque calculations, engineering and science, education.

About Foot-Pound

Foot-pound force (ft·lbf) is a unit of torque in the imperial system. It represents one pound of force acting at a distance of one foot from a pivot point.

Common uses: automotive specs, US engineering, tooling.

Frequently Asked Questions

How many Foot-Pound are in 1 Newton-Centimeter?

There are exactly 0.0073756215 Foot-Pound in 1 Newton-Centimeter. This means the conversion factor from Newton-Centimeter to Foot-Pound is 0.0073756215.

What is the formula to convert Newton-Centimeter to Foot-Pound?

The formula to convert Newton-Centimeter to Foot-Pound is: ft·lbf = N·cm × 0.0073756215. For example, to convert 10 Newton-Centimeter to Foot-Pound, you would multiply 10 by 0.0073756215.

What is a Newton-Centimeter?