38 BTU/Pound-°F to Joule/Kilogram-Kelvin
Quick answer
38 BTU/Pound-°F (BTU/(lb·°F)) equals
159,098.4 J/(kg·K)
To convert 38 BTU/Pound-°Fs to Joule/Kilogram-Kelvins, multiply by 4,186.8. Therefore, 38 BTU/Pound-°F (BTU/(lb·°F)) equals 159,098.4 Joule/Kilogram-Kelvin (J/(kg·K)).
Formula: J/(kg·K) = BTU/(lb·°F) × 4,186.8. Calculation: 38 × 4,186.8 = 159,098.4 J/(kg·K).
Convert BTU/Pound-°F (BTU/(lb·°F)) to Joule/Kilogram-Kelvin (J/(kg·K)) online with our free unit converter. In specific heat capacity, 1 BTU/(lb·°F) = 4,186.8 J/(kg·K). Explore step-by-step conversion steps, mathematical formulas, and quick conversion reference tables below.
Worked example: converting BTU/Pound-°F to Joule/Kilogram-Kelvin
- Step 1 — start with the formula. J/(kg·K) = BTU/(lb·°F) × 4,186.8
- Step 2 — substitute your figure. 38 BTU/(lb·°F) × 4,186.8
- Step 3 — read the result. 38 BTU/(lb·°F) = 159,098.4 J/(kg·K)
- Step 4 — check it in reverse. BTU/(lb·°F) = J/(kg·K) × 0.0002388459 returns Invalid BTU/(lb·°F), which matches the figure you started with.
Specific Heat Capacity Converter
6 units available
38 BTU/(lb·°F) = 159,098.4 J/(kg·K)
Formula:
J/(kg·K) = BTU/(lb·°F) × 4,186.8With your value: 38 BTU/(lb·°F) = 159,098.4 J/(kg·K)
Other BTU/Pound-°F to Joule/Kilogram-Kelvin conversions
BTU/Pound-°F to Joule/Kilogram-Kelvin Conversion Table
| BTU/Pound-°F (BTU/(lb·°F)) | Joule/Kilogram-Kelvin (J/(kg·K)) |
|---|---|
| 0.5 | 2,093.4 |
| 1 | 4,186.8 |
| 2 | 8,373.6 |
| 5 | 20,934 |
| 10 | 41,868 |
| 15 | 62,802 |
| 20 | 83,736 |
| 25 | 104,670 |
| 50 | 209,340 |
| 100 | 418,680 |
| 250 | 1,046,700 |
| 500 | 2,093,400 |
| 1000 | 4,186,800 |
Joule/Kilogram-Kelvin to BTU/Pound-°F Conversion Table
| Joule/Kilogram-Kelvin (J/(kg·K)) | BTU/Pound-°F (BTU/(lb·°F)) |
|---|---|
| 0.5 | 0.000119 |
| 1 | 0.000239 |
| 2 | 0.000478 |
| 5 | 0.001194 |
| 10 | 0.002388 |
| 15 | 0.003583 |
| 20 | 0.004777 |
| 25 | 0.005971 |
| 50 | 0.011942 |
| 100 | 0.023885 |
| 250 | 0.059711 |
| 500 | 0.119423 |
| 1000 | 0.238846 |
Where these values come from
Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.
BTU/Pound-°F (BTU/(lb·°F))
Specific Heat Capacity
Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.
Source: NIST Special Publication 811, Guide for the Use of the International System of Units
National Institute of Standards and Technology (US) · Reviewed 2026-07-01
Joule/Kilogram-Kelvin (J/(kg·K))
Specific Heat Capacity
Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.
Source: NIST Special Publication 811, Guide for the Use of the International System of Units
National Institute of Standards and Technology (US) · Reviewed 2026-07-01
How to Convert BTU/Pound-°F to Joule/Kilogram-Kelvin
To convert from BTU/Pound-°F (BTU/(lb·°F)) to Joule/Kilogram-Kelvin (J/(kg·K)), multiply the value by 4,186.8.
Formula: J/(kg·K) = BTU/(lb·°F) × 4,186.8
Reverse: BTU/(lb·°F) = J/(kg·K) × 0.0002388459
Step-by-Step Example
- Start with your value in BTU/Pound-°F. For example: 5 BTU/(lb·°F)
- Multiply by the conversion factor: 5 x 4,186.8
- The result is: 20,934 J/(kg·K)
BTU/Pound-°F and Joule/Kilogram-Kelvin Relationship
This conversion bridges the US Customary / Imperial and Metric (SI) measurement systems, commonly required when translating scientific data, international engineering specifications, or trade standards. Since 1 BTU/Pound-°F equals approximately 4,186.8 Joule/Kilogram-Kelvins, the BTU/Pound-°F represents a larger unit interval than the Joule/Kilogram-Kelvin. Understanding the relationship between BTU/Pound-°F and Joule/Kilogram-Kelvin is essential for accurate calculations in physics, engineering, commerce, and daily applications.
About BTU/Pound-°F
The BTU/Pound-°F (symbol: BTU/(lb·°F)) is a recognized unit in the US Customary / Imperial measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
Common uses of BTU/Pound-°F: specific heat capacity calculations, engineering and science, education.
About Joule/Kilogram-Kelvin
The Joule/Kilogram-Kelvin (symbol: J/(kg·K)) is a recognized unit in the Metric (SI) measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
Common uses of Joule/Kilogram-Kelvin: specific heat capacity calculations, engineering and science, education.
Frequently Asked Questions
- What is 38 BTU/Pound-°F in Joule/Kilogram-Kelvin?
- 38 BTU/Pound-°F equals 159,098.4 Joule/Kilogram-Kelvin.
- How many Joule/Kilogram-Kelvins are in 1 BTU/Pound-°F?
- There are exactly 4,186.8 Joule/Kilogram-Kelvins in 1 BTU/Pound-°F. This means the conversion factor from BTU/Pound-°F to Joule/Kilogram-Kelvin is 4,186.8.
- What is the formula to convert BTU/Pound-°F to Joule/Kilogram-Kelvin?
- The formula to convert BTU/Pound-°F to Joule/Kilogram-Kelvin is: J/(kg·K) = BTU/(lb·°F) × 4,186.8. For example, to convert 10 BTU/Pound-°Fs to Joule/Kilogram-Kelvins, you would multiply 10 by 4,186.8.
- What is a BTU/Pound-°F?
- The BTU/Pound-°F (symbol: BTU/(lb·°F)) is a recognized unit in the US Customary / Imperial measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
- What is a Joule/Kilogram-Kelvin?
- The Joule/Kilogram-Kelvin (symbol: J/(kg·K)) is a recognized unit in the Metric (SI) measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
- What are the common uses of BTU/Pound-°F?
- The BTU/Pound-°F is commonly used in specific heat capacity calculations, engineering and science, education.
Related Specific Heat Capacity Conversions
Cite this page
UnitConvertLab. (2026). 38 BTU/Pound-°F to Joule/Kilogram-Kelvin. UnitConvertLab. Retrieved from https://unitconvertlab.com/convert/38-btu_per_lb_f-to-joule_per_kg_k