Calorie/Gram-°C to BTU/Pound-°F Converter

Specific Heat Capacity Converter

6 units available

Decimals:

From

To

0.999331

1 cal/(g·°C) = 0.999331 BTU/(lb·°F)

Formula:

BTU/(lb·°F) = cal/(g·°C) × 0.9993312315

With your value: 1 cal/(g·°C) = 0.99933123 BTU/(lb·°F)

Other Calorie/Gram-°C to BTU/Pound-°F conversions

2 cal/(g·°C) to BTU/(lb·°F)3 cal/(g·°C) to BTU/(lb·°F)4 cal/(g·°C) to BTU/(lb·°F)5 cal/(g·°C) to BTU/(lb·°F)6 cal/(g·°C) to BTU/(lb·°F)7 cal/(g·°C) to BTU/(lb·°F)8 cal/(g·°C) to BTU/(lb·°F)

Calorie/Gram-°C to BTU/Pound-°F Conversion Table

Calorie/Gram-°C (cal/(g·°C))	BTU/Pound-°F (BTU/(lb·°F))
0.5	0.499666
1	0.999331
2	1.998662
5	4.996656
10	9.993312
15	14.989968
20	19.986625
25	24.983281
50	49.966562
100	99.933123
250	249.832808
500	499.665616
1000	999.331231

BTU/Pound-°F to Calorie/Gram-°C Conversion Table

BTU/Pound-°F (BTU/(lb·°F))	Calorie/Gram-°C (cal/(g·°C))
0.5	0.500335
1	1.000669
2	2.001338
5	5.003346
10	10.006692
15	15.010038
20	20.013384
25	25.01673
50	50.033461
100	100.066922
250	250.167304
500	500.334608
1000	1,000.669216

Where these values come from

Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.

Calorie/Gram-°C (cal/(g·°C))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

BTU/Pound-°F (BTU/(lb·°F))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

How to Convert Calorie/Gram-°C to BTU/Pound-°F

To convert from Calorie/Gram-°C (cal/(g·°C)) to BTU/Pound-°F (BTU/(lb·°F)), multiply the value by 0.9993312315.

Formula: BTU/(lb·°F) = cal/(g·°C) × 0.9993312315

Reverse: cal/(g·°C) = BTU/(lb·°F) × 1.0006692161

Step-by-Step Example

Start with your value in Calorie/Gram-°C. For example: 5 cal/(g·°C)
Multiply by the conversion factor: 5 x 0.9993312315
The result is: 4.996656 BTU/(lb·°F)

About Calorie/Gram-°C

The calorie/gram-°c (cal/(g·°C)) is a unit of specific heat capacity. One calorie/gram-°c equals 4184 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

About BTU/Pound-°F

The btu/pound-°f (BTU/(lb·°F)) is a unit of specific heat capacity. One btu/pound-°f equals 4186.8 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

Frequently Asked Questions

How many BTU/Pound-°F are in 1 Calorie/Gram-°C?

There are exactly 0.9993312315 BTU/Pound-°F in 1 Calorie/Gram-°C. This means the conversion factor from Calorie/Gram-°C to BTU/Pound-°F is 0.9993312315.

What is the formula to convert Calorie/Gram-°C to BTU/Pound-°F?

The formula to convert Calorie/Gram-°C to BTU/Pound-°F is: BTU/(lb·°F) = cal/(g·°C) × 0.9993312315. For example, to convert 10 Calorie/Gram-°C to BTU/Pound-°F, you would multiply 10 by 0.9993312315.

What is a Calorie/Gram-°C?