Joule/Gram-°C to BTU/Pound-°F Converter

Specific Heat Capacity Converter

6 units available

Decimals:

From

To

0.238846

1 J/(g·°C) = 0.238846 BTU/(lb·°F)

Formula:

BTU/(lb·°F) = J/(g·°C) × 0.2388458966

With your value: 1 J/(g·°C) = 0.2388459 BTU/(lb·°F)

Other Joule/Gram-°C to BTU/Pound-°F conversions

2 J/(g·°C) to BTU/(lb·°F)3 J/(g·°C) to BTU/(lb·°F)4 J/(g·°C) to BTU/(lb·°F)5 J/(g·°C) to BTU/(lb·°F)6 J/(g·°C) to BTU/(lb·°F)7 J/(g·°C) to BTU/(lb·°F)8 J/(g·°C) to BTU/(lb·°F)

Joule/Gram-°C to BTU/Pound-°F Conversion Table

Joule/Gram-°C (J/(g·°C))	BTU/Pound-°F (BTU/(lb·°F))
0.5	0.119423
1	0.238846
2	0.477692
5	1.194229
10	2.388459
15	3.582688
20	4.776918
25	5.971147
50	11.942295
100	23.88459
250	59.711474
500	119.422948
1000	238.845897

BTU/Pound-°F to Joule/Gram-°C Conversion Table

BTU/Pound-°F (BTU/(lb·°F))	Joule/Gram-°C (J/(g·°C))
0.5	2.0934
1	4.1868
2	8.3736
5	20.934
10	41.868
15	62.802
20	83.736
25	104.67
50	209.34
100	418.68
250	1,046.7
500	2,093.4
1000	4,186.8

Where these values come from

Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.

Joule/Gram-°C (J/(g·°C))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

BTU/Pound-°F (BTU/(lb·°F))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

How to Convert Joule/Gram-°C to BTU/Pound-°F

To convert from Joule/Gram-°C (J/(g·°C)) to BTU/Pound-°F (BTU/(lb·°F)), multiply the value by 0.2388458966.

Formula: BTU/(lb·°F) = J/(g·°C) × 0.2388458966

Reverse: J/(g·°C) = BTU/(lb·°F) × 4.1868

Step-by-Step Example

Start with your value in Joule/Gram-°C. For example: 5 J/(g·°C)
Multiply by the conversion factor: 5 x 0.2388458966
The result is: 1.194229 BTU/(lb·°F)

About Joule/Gram-°C

The joule/gram-°c (J/(g·°C)) is a unit of specific heat capacity. One joule/gram-°c equals 1000 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

About BTU/Pound-°F

The btu/pound-°f (BTU/(lb·°F)) is a unit of specific heat capacity. One btu/pound-°f equals 4186.8 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

Frequently Asked Questions

How many BTU/Pound-°F are in 1 Joule/Gram-°C?

There are exactly 0.2388458966 BTU/Pound-°F in 1 Joule/Gram-°C. This means the conversion factor from Joule/Gram-°C to BTU/Pound-°F is 0.2388458966.

What is the formula to convert Joule/Gram-°C to BTU/Pound-°F?

The formula to convert Joule/Gram-°C to BTU/Pound-°F is: BTU/(lb·°F) = J/(g·°C) × 0.2388458966. For example, to convert 10 Joule/Gram-°C to BTU/Pound-°F, you would multiply 10 by 0.2388458966.

What is a Joule/Gram-°C?