Joule/Gram-°C to Calorie/Gram-°C Converter

Specific Heat Capacity Converter

6 units available

Decimals:

From

To

0.239006

1 J/(g·°C) = 0.239006 cal/(g·°C)

Formula:

cal/(g·°C) = J/(g·°C) × 0.2390057361

With your value: 1 J/(g·°C) = 0.23900574 cal/(g·°C)

Other Joule/Gram-°C to Calorie/Gram-°C conversions

2 J/(g·°C) to cal/(g·°C)3 J/(g·°C) to cal/(g·°C)4 J/(g·°C) to cal/(g·°C)5 J/(g·°C) to cal/(g·°C)6 J/(g·°C) to cal/(g·°C)7 J/(g·°C) to cal/(g·°C)8 J/(g·°C) to cal/(g·°C)

Joule/Gram-°C to Calorie/Gram-°C Conversion Table

Joule/Gram-°C (J/(g·°C))	Calorie/Gram-°C (cal/(g·°C))
0.5	0.119503
1	0.239006
2	0.478011
5	1.195029
10	2.390057
15	3.585086
20	4.780115
25	5.975143
50	11.950287
100	23.900574
250	59.751434
500	119.502868
1000	239.005736

Calorie/Gram-°C to Joule/Gram-°C Conversion Table

Calorie/Gram-°C (cal/(g·°C))	Joule/Gram-°C (J/(g·°C))
0.5	2.092
1	4.184
2	8.368
5	20.92
10	41.84
15	62.76
20	83.68
25	104.6
50	209.2
100	418.4
250	1,046
500	2,092
1000	4,184

Where these values come from

Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.

Joule/Gram-°C (J/(g·°C))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

Calorie/Gram-°C (cal/(g·°C))

Specific Heat Capacity

Exact conversion

Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.

Source: NIST Special Publication 811, Guide for the Use of the International System of Units

National Institute of Standards and Technology (US) · Reviewed 2026-07-01

How to Convert Joule/Gram-°C to Calorie/Gram-°C

To convert from Joule/Gram-°C (J/(g·°C)) to Calorie/Gram-°C (cal/(g·°C)), multiply the value by 0.2390057361.

Formula: cal/(g·°C) = J/(g·°C) × 0.2390057361

Reverse: J/(g·°C) = cal/(g·°C) × 4.184

Step-by-Step Example

Start with your value in Joule/Gram-°C. For example: 5 J/(g·°C)
Multiply by the conversion factor: 5 x 0.2390057361
The result is: 1.195029 cal/(g·°C)

About Joule/Gram-°C

The joule/gram-°c (J/(g·°C)) is a unit of specific heat capacity. One joule/gram-°c equals 1000 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

About Calorie/Gram-°C

The calorie/gram-°c (cal/(g·°C)) is a unit of specific heat capacity. One calorie/gram-°c equals 4184 base units. UnitConvertLab converts it against every other specific heat capacity unit using this exact definition, so results are reproducible to full double precision rather than rounded lookup tables.

Common uses: specific heat capacity calculations, engineering and science, education.

Frequently Asked Questions

How many Calorie/Gram-°C are in 1 Joule/Gram-°C?

There are exactly 0.2390057361 Calorie/Gram-°C in 1 Joule/Gram-°C. This means the conversion factor from Joule/Gram-°C to Calorie/Gram-°C is 0.2390057361.

What is the formula to convert Joule/Gram-°C to Calorie/Gram-°C?

The formula to convert Joule/Gram-°C to Calorie/Gram-°C is: cal/(g·°C) = J/(g·°C) × 0.2390057361. For example, to convert 10 Joule/Gram-°C to Calorie/Gram-°C, you would multiply 10 by 0.2390057361.

What is a Joule/Gram-°C?