30 Calorie/Gram-°C to Joule/Kilogram-Kelvin
Quick answer
30 Calorie/Gram-°C (cal/(g·°C)) equals
125,520 J/(kg·K)
To convert 30 Calorie/Gram-°Cs to Joule/Kilogram-Kelvins, multiply by 4,184. Therefore, 30 Calorie/Gram-°C (cal/(g·°C)) equals 125,520 Joule/Kilogram-Kelvin (J/(kg·K)).
Formula: J/(kg·K) = cal/(g·°C) × 4,184. Calculation: 30 × 4,184 = 125,520 J/(kg·K).
Convert Calorie/Gram-°C (cal/(g·°C)) to Joule/Kilogram-Kelvin (J/(kg·K)) online with our free unit converter. In specific heat capacity, 1 cal/(g·°C) = 4,184 J/(kg·K). Explore step-by-step conversion steps, mathematical formulas, and quick conversion reference tables below.
Worked example: converting Calorie/Gram-°C to Joule/Kilogram-Kelvin
- Step 1 — start with the formula. J/(kg·K) = cal/(g·°C) × 4,184
- Step 2 — substitute your figure. 30 cal/(g·°C) × 4,184
- Step 3 — read the result. 30 cal/(g·°C) = 125,520 J/(kg·K)
- Step 4 — check it in reverse. cal/(g·°C) = J/(kg·K) × 0.0002390057 returns Invalid cal/(g·°C), which matches the figure you started with.
Specific Heat Capacity Converter
6 units available
30 cal/(g·°C) = 125,520 J/(kg·K)
Formula:
J/(kg·K) = cal/(g·°C) × 4,184With your value: 30 cal/(g·°C) = 125,520 J/(kg·K)
Other Calorie/Gram-°C to Joule/Kilogram-Kelvin conversions
Calorie/Gram-°C to Joule/Kilogram-Kelvin Conversion Table
| Calorie/Gram-°C (cal/(g·°C)) | Joule/Kilogram-Kelvin (J/(kg·K)) |
|---|---|
| 0.5 | 2,092 |
| 1 | 4,184 |
| 2 | 8,368 |
| 5 | 20,920 |
| 10 | 41,840 |
| 15 | 62,760 |
| 20 | 83,680 |
| 25 | 104,600 |
| 50 | 209,200 |
| 100 | 418,400 |
| 250 | 1,046,000 |
| 500 | 2,092,000 |
| 1000 | 4,184,000 |
Joule/Kilogram-Kelvin to Calorie/Gram-°C Conversion Table
| Joule/Kilogram-Kelvin (J/(kg·K)) | Calorie/Gram-°C (cal/(g·°C)) |
|---|---|
| 0.5 | 0.00012 |
| 1 | 0.000239 |
| 2 | 0.000478 |
| 5 | 0.001195 |
| 10 | 0.00239 |
| 15 | 0.003585 |
| 20 | 0.00478 |
| 25 | 0.005975 |
| 50 | 0.01195 |
| 100 | 0.023901 |
| 250 | 0.059751 |
| 500 | 0.119503 |
| 1000 | 0.239006 |
Where these values come from
Every factor on this page is traced to the document that defines it. See the full provenance dataset or our methodology.
Calorie/Gram-°C (cal/(g·°C))
Specific Heat Capacity
Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.
Source: NIST Special Publication 811, Guide for the Use of the International System of Units
National Institute of Standards and Technology (US) · Reviewed 2026-07-01
Joule/Kilogram-Kelvin (J/(kg·K))
Specific Heat Capacity
Derived quantity, joule per kilogram-kelvin (J/(kg·K)). Calorie- and BTU-based units use the thermochemical calorie (4.184 J exactly) and the International Table BTU.
Source: NIST Special Publication 811, Guide for the Use of the International System of Units
National Institute of Standards and Technology (US) · Reviewed 2026-07-01
How to Convert Calorie/Gram-°C to Joule/Kilogram-Kelvin
To convert from Calorie/Gram-°C (cal/(g·°C)) to Joule/Kilogram-Kelvin (J/(kg·K)), multiply the value by 4,184.
Formula: J/(kg·K) = cal/(g·°C) × 4,184
Reverse: cal/(g·°C) = J/(kg·K) × 0.0002390057
Step-by-Step Example
- Start with your value in Calorie/Gram-°C. For example: 5 cal/(g·°C)
- Multiply by the conversion factor: 5 x 4,184
- The result is: 20,920 J/(kg·K)
Calorie/Gram-°C and Joule/Kilogram-Kelvin Relationship
This calculation facilitates standardized conversion between recognized units of specific heat capacity. Since 1 Calorie/Gram-°C equals approximately 4,184 Joule/Kilogram-Kelvins, the Calorie/Gram-°C represents a larger unit interval than the Joule/Kilogram-Kelvin. Understanding the relationship between Calorie/Gram-°C and Joule/Kilogram-Kelvin is essential for accurate calculations in physics, engineering, commerce, and daily applications.
About Calorie/Gram-°C
The Calorie/Gram-°C (symbol: cal/(g·°C)) is a recognized unit in the Standard measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
Common uses of Calorie/Gram-°C: specific heat capacity calculations, engineering and science, education.
About Joule/Kilogram-Kelvin
The Joule/Kilogram-Kelvin (symbol: J/(kg·K)) is a recognized unit in the Metric (SI) measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
Common uses of Joule/Kilogram-Kelvin: specific heat capacity calculations, engineering and science, education.
Frequently Asked Questions
- What is 30 Calorie/Gram-°C in Joule/Kilogram-Kelvin?
- 30 Calorie/Gram-°C equals 125,520 Joule/Kilogram-Kelvin.
- How many Joule/Kilogram-Kelvins are in 1 Calorie/Gram-°C?
- There are exactly 4,184 Joule/Kilogram-Kelvins in 1 Calorie/Gram-°C. This means the conversion factor from Calorie/Gram-°C to Joule/Kilogram-Kelvin is 4,184.
- What is the formula to convert Calorie/Gram-°C to Joule/Kilogram-Kelvin?
- The formula to convert Calorie/Gram-°C to Joule/Kilogram-Kelvin is: J/(kg·K) = cal/(g·°C) × 4,184. For example, to convert 10 Calorie/Gram-°Cs to Joule/Kilogram-Kelvins, you would multiply 10 by 4,184.
- What is a Calorie/Gram-°C?
- The Calorie/Gram-°C (symbol: cal/(g·°C)) is a recognized unit in the Standard measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
- What is a Joule/Kilogram-Kelvin?
- The Joule/Kilogram-Kelvin (symbol: J/(kg·K)) is a recognized unit in the Metric (SI) measurement framework, utilized within specific heat capacity applications for precision and standardized data representation.
- What are the common uses of Calorie/Gram-°C?
- The Calorie/Gram-°C is commonly used in specific heat capacity calculations, engineering and science, education.
Related Specific Heat Capacity Conversions
Cite this page
UnitConvertLab. (2026). 30 Calorie/Gram-°C to Joule/Kilogram-Kelvin. UnitConvertLab. Retrieved from https://unitconvertlab.com/convert/30-cal_per_g_c-to-joule_per_kg_k